# How many grams of carbon monoxide can you produce from 3 grams of carbon and an excess of oxygen?

Aug 28, 2016

About $7$ $g$ of $C O$,

#### Explanation:

We need (i) a stoichiometric equation:

$C \left(s\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow C O \left(g\right)$

And now (ii) we need the equivalent quantity of $C$.

$\text{Moles of carbon}$ $=$ $\frac{3.0 \cdot g}{12.011 \cdot g \cdot m o {l}^{-} 1}$ $=$ $\frac{1}{4} \cdot \text{mole}$.

So mass of carbon monoxide $=$ $\frac{1}{4} \cdot m o l \times 28 \cdot g \cdot m o {l}^{-} 1$ $=$ $7 \cdot g$.