# How many grams of CH_4 at STP would ﬁll a 1.00 L ﬂask?

Dec 29, 2015

$m = 0.714 g \text{ of } C {H}_{4}$

#### Explanation:

At STP, the molar volume is equal to $22.42 \text{L/mol}$, therefore, to calculate the number of mole of $C {H}_{4}$ that fill a 1.00L flask by:

?mol=1.00cancel(L)xx(1mol)/(22.42cancel(L))=0.0446 mol

Now, to calculate the mass of $C {H}_{4}$ in question:

?g=0.0446cancel(mol)xx(16.01g)/(1cancel(mol))=0.714g " of " CH_4