# How many grams of #CuSO_4# are present in 652 mL of .250 M #CuSO_4# solution?

##### 2 Answers

Approx.

#### Explanation:

We use the defining quotient....

And thus

And for

And with respect to

Of course in an aqueous solution of copper sulfate, the copper is present as

#### Explanation:

Given the molarity

#M=eta/V# where:

#eta=("mass"(m))/("molar mass"(Mm))#

Now, plug in this value to the formula. Rearrange formula to isolate

#M=((m)/(Mm))/V# ; cross multiply to simplify

#MV=m/(Mm# ; isolate the required variable#m#

#m=MVMm# ; now, plug in the values of each variablewhere:

#M=0.250M=(0.250mol)/(L)#

#V=652cancel(mL)xx(1L)/(1000cancel(mL))=0.652L#

#Mm_(CuSO_4)=(159.5g)/(mol)# , obtainable from the periodic table.

#m=(0.250cancel(mol))/cancel(L)xx0.652cancel(L)xx(159.5g)/cancel(mol)#

#m=ul ?g CuSO_4#