How many grams of glucose are in #6.63 xx 10^23# molecules of glucose, #C_6H_12O_6#?

1 Answer

Answer:

198 g of Glucose

Explanation:

We have to convert #6.63*10^23# molecules of glucose into moles first.

To do this, we have to divide the number of molecules of glucose by Avogadro's Constant, #6.023 * 10^23#, which is the number of molecules of any substance in a mole of that substance.

#(6.63*10^23 "molecules")/(6.023 * 10^23 "molecules/mol") = "1.101 mol"# of glucose.

Then we can use the moles equation, Moles #= (Mass)/(RMM)#

#"1.101 mol" = (Mass)/([(6*12.01)+(12*1.008)+(6*16.00)] "g/mol")#

#"1.101 mol" = (Mass)/"180.16 g/mol"#

#Mass = "1.101 mol" * "180.16 g/mol"#

#Mass = "198 g"#