Question

How many grams of glucose are in `6.63 xx 10^23` molecules of glucose, `C_6H_12O_6`?

Answer 1

198 g of Glucose

Explanation:

We have to convert `6.63*10^23` molecules of glucose into moles first.

To do this, we have to divide the number of molecules of glucose by Avogadro's Constant, `6.023 * 10^23`, which is the number of molecules of any substance in a mole of that substance.

`(6.63*10^23 "molecules")/(6.023 * 10^23 "molecules/mol") = "1.101 mol"` of glucose.

Then we can use the moles equation, Moles `= (Mass)/(RMM)`

`"1.101 mol" = (Mass)/([(6*12.01)+(12*1.008)+(6*16.00)] "g/mol")`

`"1.101 mol" = (Mass)/"180.16 g/mol"`

`Mass = "1.101 mol" * "180.16 g/mol"`

`Mass = "198 g"`