How many grams of H_3PO_4 are in 175 mL of a 3.5 M solution of H_3PO_4?

Apr 4, 2018

Around $60$ grams.

Explanation:

We have a $3.5 \setminus \text{M}$ solution of phosphoric acid with 175 \ "mL of it in there. This means that there are:

(3.5 \ "mol")/(color(red)cancelcolor(black)"L")*0.175color(red)cancelcolor(black)"L"=0.6125 \ "mol"

So, there exist $0.6125$ moles of phosphoric acid here.

Phosphoric acid has a molar mass of $97.994 \setminus \text{g/mol}$.

So here, the mass is:

$0.6125 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{mol"*(97.994 \ "g")/(color(red)cancelcolor(black)"mol")~~60 \ "g}}}}$