Question

How many grams of magnesium phosphate (Mg3(PO4)2) will be produced from the reaction of magnesium with 54.21g of phosphoric acid (H3PO4) ?

Answer 1

`0.3305"mol"`

Explanation:

First we need to write the balanced equation.
`3Mg + 2H_3PO_4 rarr Mg_3(PO4)_2 +3H_2`

Now we need to find how many moles are in 54.21g of phosphoric acid.
`54.21"g" * "1mol"/"82.00g" = 0.6611"mol"`

Now that we have the moles, we can check how much magnesium phosphate is produced.

`0.6611"mol" * "1mol"_(Mg_3(PO4)_2)/"2mol" = 0.3305"mol"`