# How many grams of NaCl are needed to make .1 L of 1.20 M solution of NaCl?

Approx. $7 \cdot g$
$\text{Moles of sodium chloride}$ $=$ $0.1 \cdot L \times 1.20 \cdot m o l \cdot {L}^{-} 1 = 0.12 \cdot m o l$.
$\text{Mass of sodium chloride}$ $=$ $0.12 \cdot m o l \times 58.44 \cdot g \cdot m o {l}^{-} 1$ $=$ ?g