# How many grams of NaCl are present in 14.65 moles?

Dec 18, 2015

In $1$ mol of $N a C l$ there are 58.44 g. So $58.44$ $\times$ ????
We have a formula mass in $g \cdot m o {l}^{-} 1$, and a $14.65$ $m o l$ quantity of $N a C l$.
The mass is simply the product: $14.65 \cdot \cancel{m o l} \times 58.44 \cdot g \cdot \cancel{m o {l}^{-} 1}$ $=$ ???g.