How many grams of NaCl are present in 14.65 moles?

1 Answer
Dec 18, 2015

Answer:

In #1# mol of #NaCl# there are 58.44 g. So #58.44# #xx# #????#

Explanation:

We have a formula mass in #g*mol^-1#, and a #14.65# #mol# quantity of #NaCl#.

The mass is simply the product: #14.65*cancel(mol)xx58.44*g*cancel(mol^-1)# #=# #???g#.

When we use units in the calculation like this, we introduce an extra safeguard in that if the answer simplifies to moles we know we have not divided when we should have multiplied.