How many grams of NaCl are present in 350 mL of 0.020 M NaCL solution? (Remember that 1 mole NaCL = 58.44 grams g/mole.)?
As stated, 1 mole of NaCl weighs 58.44 g.
A 0.02 M solution contains 0.02 moles per liter.
Hence, 1 litre would contain:
58.44 x 0.02 = 1.1688 g
However, there are only 350 ml, which is 0.35 liters.
Therefore, there would be 0.35 x 1.1688 g in total, 0.409 g
For further help this blog post on moles and molarity may be useful.
The 350 mL solution will contain 0.4 g NaCl.
The symbol for molarity, M, represents the units mol/L. When you perform equations involving molarity, use the units mol/L. The 0.02 M solution is said to be 0.02 molar, and is 0.02 mol/L.
In order to determine the moles of NaCl in the 0.35 L solution, multiply
In order to determine the mass of the NaCl in the 0.35 L NaCl solution, multiply the moles of