How many grams of NaOH are in 4.35 moles?

$1$ mole of sodium hydroxide has a mass of $40.00$ $g \cdot m o {l}^{-} 1$.
If you have $4.35$ $m o l$, then $4.35 \cancel{m o l}$ $\times$ $40.00$ $g \cdot \cancel{m o {l}^{- 1}}$ $=$ ??g