How many grams of NaOH are needed to prepare 250 mL of 0.205 M NaOH?

1 Answer
Feb 28, 2017

Answer:

A bit over #2*g#...............

Explanation:

#"Concentration"# #=# #"Moles of solute (moles)"/"Volume of solution (L)"#

Thus #"Concentration"xx"volume"="moles of solute"#

#0.205*mol*cancel(L^-1)xx0.250*cancelL="Moles of solute"#

#=0.0513*mol#, an answer in moles as required.

And thus #"mass of NaOH"# #=# #"moles "xx" molar mass"#

#=0.0513*cancel(mol)xx40.0*g*cancel(mol^-1)#

#=2.05*g#