# How many grams of NH_3 will have the same number of molecules as 15.0 g of C_6H_6?

Oct 1, 2016

Approx. $3 \cdot g$ $\text{ammonia}$ are required.

#### Explanation:

We need equimolar quantities of ammonia and benzene.

$\text{Moles of benzene}$ $=$ $\frac{15.0 \cdot g}{78.11 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.192 \cdot m o l$.

And thus we need $0.192 \cdot m o l \times 17.03 \cdot g \cdot m o {l}^{-} 1 \text{ ammonia}$ $=$ ??g

How many ammonia and benzene molecules are there in this molar quantity?