How many grams of #NH_3# will have the same number of molecules as 15.0 g of #C_6H_6#?

1 Answer
Oct 1, 2016

Answer:

Approx. #3*g# #"ammonia"# are required.

Explanation:

We need equimolar quantities of ammonia and benzene.

#"Moles of benzene"# #=# #(15.0*g)/(78.11*g*mol^-1)# #=# #0.192*mol#.

And thus we need #0.192*molxx17.03*g*mol^-1" ammonia"# #=# #??g#

How many ammonia and benzene molecules are there in this molar quantity?