How many grams of nitric acid are present in 250.0 mL of 6.70 M acid solution?

1 Answer
Feb 10, 2016

Answer:

Approx. 100 g.

Explanation:

#"Concentration", mol*L^-1# #=# #"Moles(n)"/"Volume of solution(L)"#.

Clearly, #n#, #"No. of moles"# #=# #"Concentration "xx" Volume"#.

So, #250xx10^(-3)cancelLxx6.70*mol*cancelL^-1# #=# #??# #mol# #HNO_3#.

And now, multiply that molar quantity by the molar mass of nitric acid, #63.01*g*mol^-1#.

#??# #mol# #xx# #63.01*g*mol^-1# #=# #??# #g#?