How many grams of #O# are contained in 8.52 g #K_2CO_3#?

1 Answer
Nov 12, 2015

Answer:

In 1 mole of potassium carbonate there are clearly 3 moles of oxygen atoms (i.e. 48.00 g), almost half the mass of 1 mol of the salt.

Explanation:

Moles of #K_2CO_3# #=# #(8.52*g)/(131.21*g*mol^-1)# #=# #??# #mol#.

But there are 3 mol of oxygen in each mole of #K_2CO_3#.

So moles of oxygen #=# #3xx(8.52*g)/(131.21*g*mol^-1) = ?? mol#.