How many grams of oxygen are needed to produce .60 liters of carbon dioxide at stp?
Well, of course, we need to define
...which is hard these days, because the professional bodies have conspired to make the definitions as confusing and as inaccessible as possible.
IUPAC specifies a temperature of
And so if we gots the combustion reaction....
When you sit an exam, the standard that you use, including the molar volume, should be printed as supplementary material.
You need 0.86 grams of oxygen to produce 0.60 liters of carbon dioxide at STP.
Oxygen has a molar mass of 16.00 g/mol. One mole of CO2 contains 32.00 grams of oxygen.
One mole equals 22.4L at standard temperature and pressure.
0.60L CO2 equals 0.0268 mol at STP.
(32g O) x (0.0268 mol) = 0.8576 g O