Question

How many grams of oxygen will be produced by decomposing 96gram of potasium chlorate? Thanks

Answer 1

We need (i) a stoichiometric equation....and a little `Mn(IV)` salt is used to catalyse the rxn....

Explanation:

`KClO_3(s) + Delta stackrel(MnO_2)rarrKCl(s) + 3/2O_2(g)uarr`

And (ii) equivalent quantities of potassium chlorate....

`(96*g)/(122.55*g*mol^-1)=0.783*mol`

And thus we should a mass with respect to dioxygen gas of....

`0.783*molxx3/2xx32.0*g*mol^-1-=37.6*g`.....