Question

How many grams of silver chloride (AgCl) can be produced if you start with 4.62 grams of barium chloride (BaCl2) ? Must show all work

Answer 1

We interrogate the reaction...

`2AgNO_3(aq) + BaCl_2(aq) rarr 2AgCl(s)darr + Ba(NO_3)_2(aq)`

Explanation:

And thus 2 equiv silver chloride precipitates as a curdy white solid when 1 equiv barium chloride is added...

`"Moles of barium chloride"=(4.62*g)/(208.23*g*mol^-1)=0.0222*mol`

...and thus a mass of ..................

`2xx0.0222*molxx143.32*g*mol^-1=6.36*g` with respect to `AgCl`.