How many grams of sodium nitrate does it take to make 250 ml 6M solution?

1 Answer
May 5, 2018

#127.5~~128g#

Explanation:

By using #n=,c*v#, where:

  • #n# = number of moles (#mol#)
  • #c# = concentration(#mol# #dm^-3#)
  • #v# = volume (#dm^3#)

#6*250/1000=6/4=3/2=1.5mol#

Now we use #m=n*M_r#, where:

  • #m# = mass (#kg#)
  • #n# = number of moles (#mol#)
  • #M_r# = molar mass (#g# #mol^-1#)

#1.5*85.0=127.5~~128g#