How many grams of solid sodium hydroxide are required to make 175.00 mL of a 0.5100 M #NaOH# solution?

1 Answer
Mar 10, 2016

Answer:

You will require 3.570 g of #"NaOH"#.

Explanation:

Step 1. Calculate the moles of #"NaOH"#.

You know there are 0.5100 mol of #"NaOH"# in 1 L of solution.

In 175.00 mL of solution there are

#"0.175 00" cancel("L soln") × "0.5100 mol KCl"/(1 cancel("L soln")) = "0.089 25 mol NaOH"#

Step 2. Calculate the mass of #"NaOH"#.

The mass of 1 mol of #"NaOH"# is #"(22.99 + 16.00+ 1.008) g = 40.00 g"#.

So the mass of #"0.089 25 mol of NaOH"# is

#"0.089 25" cancel("mol NaOH") × "40.00 g NaOH"/(1 cancel("mol NaOH")) = "3.570 g NaOH"#