How many grams of #TiCl_4# are needed to produce 44.9 g of titanium?

1 Answer
anor277
Jan 5, 2017

At least #178*g# of #"titanic chloride"# are required...........

Explanation:

#"Moles of titanium"# #=# #(44.9*g)/(47.87*g*mol^-1)=0.938*mol.#

And thus we need AT LEAST an equimolar quantity of #TiCl_4#.

And this represents of equivalent mass of:

#0.938*molxx189.68*g*mol^-1=??*g.#

I think the industrial process utilizes either alkali metals or alkaline earth metals to reduce the #TiCl_4#.

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