# How many grams of TiCl_4 are needed to produce 44.9 g of titanium?

Jan 5, 2017

At least $178 \cdot g$ of $\text{titanic chloride}$ are required...........

#### Explanation:

$\text{Moles of titanium}$ $=$ $\frac{44.9 \cdot g}{47.87 \cdot g \cdot m o {l}^{-} 1} = 0.938 \cdot m o l .$

And thus we need AT LEAST an equimolar quantity of $T i C {l}_{4}$.

And this represents of equivalent mass of:

0.938*molxx189.68*g*mol^-1=??*g.

I think the industrial process utilizes either alkali metals or alkaline earth metals to reduce the $T i C {l}_{4}$.