# How many grams of water would require 2,153 joules of heat to raise its temperature from 44 °C to 81 °C? The specific heat of water is 4.184 J/g °C.

Jun 7, 2018

$\text{13.9 g}$

#### Explanation:

Use this equation

$\text{Q = mSΔT}$

Where

• $\text{Q =}$ Heat added/released
• $\text{m =}$ Mass of sample
• $\text{S =}$ Specific heat of sample
• $\text{ΔT =}$ Change in Temperature

$\text{m" = "Q"/"SΔT}$

color(white)("m") = "2153 J"/"4.184 J/g°C × (81 – 44)°C"

color(white)("m") = 13.9\ "g"