How many grams of zinc are represented by #1.807x10^24# atoms?

1 Answer
anor277
Jan 26, 2017

Well, #6.022xx10^23# #"zinc atoms"# have a mass of #65.4*g#.

Explanation:

Of course, #6.022xx10^23# #"zinc atoms"# constitutes a mole of #"zinc atoms"#, and we say that zinc metal has a molar mass of #65.4*g*mol^-1#.

So we take the quotient:

#(1.807xx10^24" zinc atoms")/(6.022xx10^23" zinc atoms"*mol^-1)xx65.4*g*mol^-1~=200*g#

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