How many grams would 13.2 moles of lead (II) nitrate weigh?

1 Answer
Jun 6, 2017

Answer:

Well #"lead nitrate"# has an equivalent mass of #331.2*g*mol^-1#

Explanation:

And how did we get this.....we summed up the individual atomic masses in #Pb(NO_3)_2#:

#{1xx207.2+2xx14.01+6xx15.999}*g*mol^-1=331.22*g*mol^-1#

.................as required...........

From where did I get the individual atomic masses? Did I just happen to know them?