# How many grams would 13.2 moles of lead (II) nitrate weigh?

Jun 6, 2017

Well $\text{lead nitrate}$ has an equivalent mass of $331.2 \cdot g \cdot m o {l}^{-} 1$

#### Explanation:

And how did we get this.....we summed up the individual atomic masses in $P b {\left(N {O}_{3}\right)}_{2}$:

$\left\{1 \times 207.2 + 2 \times 14.01 + 6 \times 15.999\right\} \cdot g \cdot m o {l}^{-} 1 = 331.22 \cdot g \cdot m o {l}^{-} 1$

.................as required...........

From where did I get the individual atomic masses? Did I just happen to know them?