How many individual atoms are in a sample of xenon that has a mass of 38.54 grams?

1 Answer
anor277
Mar 21, 2016

There are approx. #1/3xxN_A# xenon atoms, where #N_A# #=# #"Avogadro's number"#, #=6.022xx10^23*mol^-1#

Explanation:

Elemental xenon has an equivalent mass of #131.29# #g*mol^-1#. What does this mean? It means that #"Avogadro's number"# of xenon atoms has a mass of #131.29*g#.

You have a #38.54*g# mass. Thus there are:

#(38.54*g)/(131.29*g*mol^-1)xxN_A# #=#

#(38.54*g)/(131.29*g*mol^-1)xx6.022xx10^23*mol^-1# #=# #??# #"xenon atoms?"#

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