How many ions are there in 4.5 g of #(NH_4)_3PO_4#?

1 Answer
anor277
May 4, 2016

Approx. #0.121*mol# of phosphate and ammonium ions.

Explanation:

The formula mass of ammonium phosphate is #149.09*g*mol^-1#. A mass of #4.5*g# corresponds to a molar quantity of #(4.5*g)/(149.09*g*mol^-1)# #=# #3.02xx10^(-2)*mol# with respect to #(NH_4)_3PO_4#, and thus #3.02xx10^(-2)xx4=0.121*mol# of ions, given that there are 4 individual ion per formula unit of ammonium phosphate.

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