How many ions are there in a solution with 9.656 mol of #Ni^(2+)#?

1 Answer
Mar 8, 2016

Clearly there are #9.656# #mol# of #Ni^(2+)#. But #Ni^(2+)# is not the only ion present.

Explanation:

How do I know this? Because #Ni^(2+)# must have a counterion. This could have been halide, or nitrate, or acetate, or something else.

The number of #Ni^(2+)# ions is #N_A# #xx# #9.656# #mol#. #N_A# is Avogadro's number #=# #6.022xx10^23*mol^-1#. So the number of ions is rather large.