How many joules are needed to boil 59.8 g of ethanol if the heat of vaporization is 854 J/g?

1 Answer
Jun 26, 2017

51,069.2 J


Use the heat of vaporization formula: #q = m * H_v#

The heat of vaporization of ethanol is 854 J/g (given in the question), which means that it takes 854 joules of energy to vaporize one gram of ethanol.

Since we have 59.8 grams of ethanol, plug 59.8 into the formula and multiply by 854.

#q = (59.8)(854)#
#q = 51069.2 # J

That's your answer!