How many joules need to be added to 4.50 g of lead to raise its tempurature by 25K?

what is the formula to determine this?

1 Answer
Junaid Mirza
May 10, 2018

#"14.4 J"#

Explanation:

Formula: #"Q = mSΔT"#

Where

  • #"Q ="# Energy required/released
  • #"m ="# Mass of sample
  • #"S ="# Specific heat of sample (#"0.128 J/(g K)"# for lead)
  • #"ΔT ="# Change in Temperature

#"Q" = 4.50 cancel"g" × 0.128 "J"/(cancel"g" cancel"K") × 25 cancel"K" = "14.4 J"#

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