# How many kilojoules of heat are required to vaporize 50.0 g of ethanol, C_2H_6O? The boiling point of ethanol is 78.3°C. Its molar heat of vaporization is 38.6 kJ/mol.

May 11, 2017

We want the enthalpy associated with the reaction.........

#### Explanation:

$\text{H"_3"CCH"_2"OH"(l) +Delta rarr "H"_3"CCH"_2"OH} \left(g\right)$

You have a mass of $50.0 \cdot g$ $\text{EtOH}$, that is assumed to be at $78.3$ ""^@C, and the enthalpy of vaporization is calculated by the product:

$\Delta {H}_{\text{vaporization}}^{\circ} = \frac{50.0 \cdot g}{46.07 \cdot g \cdot m o {l}^{-} 1} \times 38.6 \cdot k J \cdot m o {l}^{-} 1 =$

=??*kJ.