How many kilojoules of heat are required to vaporize 50.0 g of ethanol, #C_2H_6O#? The boiling point of ethanol is 78.3°C. Its molar heat of vaporization is 38.6 kJ/mol.

1 Answer
May 11, 2017

Answer:

We want the enthalpy associated with the reaction.........

Explanation:

#"H"_3"CCH"_2"OH"(l) +Delta rarr "H"_3"CCH"_2"OH"(g)#

You have a mass of #50.0*g# #"EtOH"#, that is assumed to be at #78.3# #""^@C#, and the enthalpy of vaporization is calculated by the product:

#DeltaH_"vaporization"^@=(50.0*g)/(46.07*g*mol^-1)xx38.6*kJ*mol^-1=#

#=??*kJ#.