How many liter/s of HCl solution can be prepared from a 5N HCl solution which contain 2.657 gram equiv HCl?

1 Answer
Al E.
Jan 25, 2018

You have,

#2.657g * ("mol")/(36.45g) approx 0.07289"mol"#

of hydrochloric acid available.

Moreover, you (seemingly) desire #5M# concentration in your solution. Hence, you can only make,

#(0.07289"mol")/L * L/(5"mol") approx 0.01458L#

of #5M# hydrochloric acid solution may be made given your data.

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