# How many liters do 3.60xx10^(24) molecules of "O"_2 occupy at STP?

May 28, 2017

The $\text{molar volume at STP}$ is $22.4 \cdot L$......And thus there are approx. $134 \cdot L$ of oxygen gas........

#### Explanation:

So to address your question, we (i) work out the molar quantity of $\text{dioxygen gas.......}$

$\text{Moles of dioxygen}$ $=$ $\left(3.60 \times {10}^{24} \cdot \text{molecules")/(6.022xx10^23*"molecules} \cdot m o {l}^{-} 1\right)$ $=$ $6.0 \cdot m o l .$

And then (ii) we take the product:

6.0*cancel(mol)xx22.4*L*cancel(mol^-1)=??

@Kathryn, the formatting here is sometimes infuriating.....you are not the only person to find it difficult.