Question

How many liters of a .88 M solution can be made with 25.5 grams of lithium fluoride (`LiF`)?

Answer 1

`L = 1.10 L` of solution

Explanation:

The Molarity `M` is calculated by the equation comparing moles of solute to liters of solution

`M=(mol)/L`

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94
F = 19.0

LiF = 25.94 g/mole

`25.2 cancel(grams) x (1 mol)/(25.94cancel(grams))` = `0.97` moles

Now we can take the the molarity and the moles and calculate the Liters of solution

`M=(mol)/L`

`ML= mol`

`L = (mol)/M`

`L = (0.97mol)/(0.88M)`

`L = 1.10 L` of solution