How many lone pairs of electrons are on the P atom in PF3? A) 2 B) 1 C) 0 D)3

1 Answer
Apr 20, 2015

The answer is B) 1.

The number of valence electrons is 5 + 3×7 = 26.

If you draw a trial structure in which P is the central atom and every atom has an octet, you will have used 26 electrons.

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This is the correct number of electrons, so the trial structure is the correct structure.

The P atom in #"PF"_3# has one lone pair of electrons.