How many moles are in 96.00 g of methane?

Jan 4, 2017

Answer:

Approx. $6 \cdot m o l$.

Explanation:

$\text{Number of moles}$ $=$ $\text{Mass of methane"/"Molar mass of methane}$

$= \frac{96.00 \cdot \cancel{g}}{\left(12.011 + 4 \times 1.00794\right) \cdot \cancel{g} \cdot m o {l}^{-} 1}$

=??mol

Note that the quotient is dimensionally consistent. We want an answer in moles, and we get an answer in $\frac{1}{m o {l}^{-} 1} = m o l$ as required.

At $S T P$, what volume would this quantity of methane occupy?