Question

How many moles of Calcium Chloride would be used in the making of 5.00 cm^3 of a 3.20 M solution?

Answer 1

Approx. `0.160*mol`

Explanation:

By definition...`"concentration"="moles of solute"/"volume of solution"`

And so `"moles of solute"="volume"xx"concentration"`...

`-=5.00*cancel(cm^3)xx10^-3*cancelL*cancel(cm^-3)xx3.20*mol*cancel(L^-1)`

`-=0.0160*mol`

And this represents a mass of....

`0.0160*molxx110.98*g*mol^-1=1.78*g`...