How many millilieters of a 12% (v/v) propyl alcohol solution would you need to obtain 5.7 mL of propyl alcohol?
In your case, a
This means that in order to have
#5.7 color(red)(cancel(color(black)("mL solute"))) * "100 mL solution"/(12color(red)(cancel(color(black)("mL solute")))) = color(darkgreen)(ul(color(black)("48 mL solution")))#
The answer is rounded to two sig figs.