How many millliters of 275 M #H_2SO_4(aq)# are needed to react completely with 58.5 g of #BaO_2(s)#?

1 Answer
anor277
Jul 7, 2016

Are you sure mean barium peroxide, #BaO_2#, and not barium oxide, #BaO#.

Explanation:

#BaO_2(s) + H_2SO_4(aq) rarr BaSO_4darr + H_2O_2(aq)#

This used to be used as an industrial method to make hydrogen peroxide.

So #"moles of barium peroxide"# #=# #(58.5*g)/(169.33*g*mol^-1)# #=# #0.345*mol#.

We need #1# #"equiv"# sulfuric acid.

If #0.275*mol*L^-1# sulfuric acid is available, we need #(0.345*mol)/(0.275*mol*L^-1)xx1000*mL*L^-1# #=# #1255*mL#.

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