# How many molecules are in 0.454 kg of carbon dioxide?

Jun 13, 2016

How many molecules in a pound of carbon dioxide?

$\frac{454 \cdot g}{44.0 \cdot g \cdot m o {l}^{-} 1} \times {N}_{A}$, where ${N}_{A} = 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.

#### Explanation:

${N}_{A}$ $=$ $\text{Avogadro's number}$ $=$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$. By definition, in $44.0 \cdot g$ of carbon dioxide there are $\text{Avogadro's number}$ of carbon atoms, and $2 \times \text{Avogadro's number}$ of oxygen atoms.

So we simply calculate the product:

$\frac{454 \cdot g}{44.0 \cdot g \cdot m o {l}^{-} 1} \times {N}_{A}$ $\cong$ $10 {N}_{A}$