# How many molecules are in 1.00 mg of glucose, C_6H_12O_6?

Dec 30, 2015

The molar mass of glucose is $\left(6 \times 12.011 + 12 \times 1.0794 + 6 \times 15.99\right) \cdot g \cdot m o {l}^{- 1}$. You have a milligram mass.

#### Explanation:

So, in 1 mol there are Avogadro's number of molecules, i.e. $6.022 \times {10}^{23} m o {l}^{-} 1$ $=$ ${N}_{A}$.

So onto our calculation:

(1.00xx10^(-3)cancel(g)xxN_A*"molecules"*cancel(mol^-1))/((6xx12.011+12xx1.0794+6xx15.99)*cancel(g*mol^(-1)) $=$

??  glucose molecules.