# How many molecules are in 7.8 moles of NH_3?

In one mole there are $6.022 \times {10}^{23}$ ammonia particles. So in $7.8$ $m o l$ there are approx. $48 \times {10}^{23}$ such particles.
So $7.8$ $\cancel{m o l}$ $\times$ $6.022$ $\times$ ${10}^{23}$ particles $\cancel{m o {l}^{-} 1}$ $=$ ?? particles? How many atoms in such a quantity.