How many molecules are in 72.00 g of #C_6H_12O_6#?

1 Answer
Mar 29, 2016

Answer:

#0.400xxN_A#, where #N_A# #=# #"Avogadro's number"#

Explanation:

Given that there are #72.00# #g#, this represents a molar quantity of #(72.00*cancelg)/(180.16*cancelg*mol^-1)# #=# #0.400# #mol#.

We simply multiply this molar quantity by #N_A" Avogadro's number"#:

#0.400*molxx6.022xx10^23*mol^-1# #=# #??#