How many molecules are in 720 g of #C_6H_12O_6#?

1 Answer
May 14, 2018

Answer:

Approx. #36xx10^23*"sugar molecules"#

Explanation:

We work out (i) the molar quantity of sugar present...

#n_"sugar"=(720*g)/(180*g*mol^-1)=6*mol#

But there are #6.022xx10^23*"particles"*mol^-1#...

...and so (ii) we take the product...

#6.022xx10^23*"particles"*mol^-1xx6*mol=?*"particles"#