How many molecules are present in 5 g of #CuSO_4 * 5H_2O#?

1 Answer
Dec 11, 2016

Answer:

In #"copper sulfate pentahydrate"#, well there are #0.020# #mol# of stuff in #5*g#.

Explanation:

#"Moles of"# #CuSO_4*5H_2O# #=# #(5*g)/(249.67*g*mol^-1)=0.020*mol.#

There are thus #0.020*mol# #Cu, and S# atoms. There are #9xx0.020*mol# oxygen atoms, and there are #10xx0.020*mol# hydrogen atoms.

Note that I am dealing with atoms not molecules.