# How many molecules are present in 936 g of glucose C_6H_12O_6?

The molar mass of ${C}_{6} {H}_{12} {O}_{6} = 6 \times 12 + 12 \times 1 + 6 \times 16 = 180 g m o {l}^{-} 1$
No. of moles $\frac{m a s s}{m o l a r m a s s} = \frac{936}{180} m o l = 5.2 m o l$
$= 5.2 \times 6.022 \times {10}^{23} \approx 31.31 \times {10}^{23}$ molecules