# How many molecules are there in 8.8 grams of SO_2?

Feb 14, 2017

Approx. $8.3 \times {10}^{22} \cdot \text{molecules of}$ $S {O}_{2} ,$

#### Explanation:

We (i) calculate the equivalent quantity of sulfur dioxide to get an answer in moles:

$\text{Moles of sulfur dioxide}$ $=$ $\frac{8.8}{64.07 \cdot g \cdot m o {l}^{-} 1} \cong \frac{1}{8} \cdot m o l$.

Then (ii) convert this molar quantity into a number of particles, knowing that $1 \cdot m o l \equiv {N}_{A}$ $\text{particles}$:

~=6.022xx10^23*mol^-1xx1/8*mol=??"molecules........."