How many molecules of dinitrogen pentoxide are in .72 moles of dinitrogen pentoxide?

Jun 11, 2016

There are ${N}_{A} \times 0.72 \text{ molecules}$ of ${N}_{2} {O}_{5}$, where ${N}_{A}$ $=$ $6.022 \times {10}^{23}$.

Explanation:

$\text{Molecules of } {N}_{2} {O}_{5}$ $=$

6.022140857(74)×10^23*cancel(mol^-1)xx0.72*cancel(mol) $=$ ??

How many $N$ atoms? How many $O$ atoms?