Question

How many molecules of ozone (O3) would be needed to fill 5.4 x1019 gram hole in the atmosphere?

Answer 1

You would need `6.8 × 10^41color(white)(l) "molecules O"_3` to fill the hole.

Explanation:

Step 1. Convert grams of ozone to moles of ozone

`"Moles of O"_3 = 5.4 × 10 ^19 color(red)(cancel(color(black)("g O"_3))) × "1 mol O"_3/(48.00 color(red)(cancel(color(black)("g O"_3)))) = 1.12 × 10^18color(white)(l) "mol O"_3`

Step 2. Convert moles of ozone to molecules of ozone

`"Molecules of O"_3 = 1.12 × 10^18 color(red)(cancel(color(black)("mol O"_3))) × (6.022 × 10^23color(white)(l) "molecules O"_3)/(1 color(red)(cancel(color(black)("mol O"_3))))`

`= 6.8 × 10^41color(white)(l) "molecules O"_3`