# How many molecules of sucrose, C_12H_22O_11, are there in 454 grams of sucrose (C_12H_22O_11)?

Mar 17, 2017

Well, for a start, $\text{sucrose}$ is ${C}_{12} {H}_{22} {O}_{11}$.

#### Explanation:

And we have to calculate the number of moles of sucrose present in a $\text{lb}$ mass of sucrose:

$\text{Moles of sucrose} = \frac{454 \cdot g}{342.30 \cdot g \cdot m o {l}^{-} 1} = 1.33 \cdot m o l$.

Now it is a fact that in a $\text{mole}$ of stuff there are $6.022 \times {10}^{23}$ individual items of stuff.........

So $1.33 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 \cong 8 \times {10}^{23}$ $\text{individual}$ $\text{sucrose molecules.}$

How many carbon atoms in such a quantity?