How many molecules of sucrose, #C_12H_22O_11#, are there in 454 grams of sucrose (#C_12H_22O_11#)?

1 Answer
anor277
Mar 17, 2017

Well, for a start, #"sucrose"# is #C_12H_22O_11#.

Explanation:

And we have to calculate the number of moles of sucrose present in a #"lb"# mass of sucrose:

#"Moles of sucrose"=(454*g)/(342.30*g*mol^-1)=1.33*mol#.

Now it is a fact that in a #"mole"# of stuff there are #6.022xx10^23# individual items of stuff.........

So #1.33*molxx6.022xx10^23*mol^-1~=8xx10^23# #"individual"# #"sucrose molecules."#

How many carbon atoms in such a quantity?

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