How many moles are contained in 22.23 g #KBr#?

1 Answer
Apr 16, 2016

Answer:

Approx. #0.20# #mol#.

Explanation:

#"No. of moles"# #=# #"Mass"/"Molar Mass"# #=# #(22.23*cancelg)/(119.00*cancelg*mol^-1)# #=# #??*mol#.

A long time ago I was told that if you owned a champion greyhound, and you did not want him to run as well as he might in a big race, then you dose the brute with bromide ion. Clearly this advice was unethical and illegal.