# How many moles are equivalent to 2.50 * 10^20 atoms of Fe?

Jun 13, 2016

There are 6.022140857(74)×10^23 $F e$ atoms in $1$ $m o l$ of iron.

#### Explanation:

So we take the quotient:

$\left(2.50 \times {10}^{20} \text{ iron atoms")/(6.022140857(74)×10^23" iron atoms} \cdot m o {l}^{-} 1\right)$

$=$ ??mol

What is the mass of this molar quantity of iron.