How many moles are equivalent to #2.50 * 10^20# atoms of #Fe#?

1 Answer
anor277
Jun 13, 2016

There are #6.022140857(74)×10^23# #Fe# atoms in #1# #mol# of iron.

Explanation:

So we take the quotient:

#(2.50xx10^20" iron atoms")/(6.022140857(74)×10^23" iron atoms"*mol^-1)#

#=# #??mol#

What is the mass of this molar quantity of iron.

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